(x^2-4)/(x-2)=4

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Solution for (x^2-4)/(x-2)=4 equation: 


D( x )

x-2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

(x^2-4)/(x-2) = 4 // - 4

(x^2-4)/(x-2)-4 = 0

(x^2-4)/(x-2)+(-4*(x-2))/(x-2) = 0

x^2-4*(x-2)-4 = 0

x^2-4*x+4 = 0

x^2-4*x+4 = 0

x^2-4*x+4 = 0

DELTA = (-4)^2-(1*4*4)

DELTA = 0

x = 4/(1*2)

x = 2 or x = 2

(x-2)^2 = 0

((x-2)^2)/(x-2) = 0

((x-2)^2)/(x-2) = 0 // * x-2

(x-2)^2 = 0

x-2 = 0 // + 2

x = 2

x in { 2} 

x belongs to the empty set

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